Question

a square has a perimeter of 36 in in a smaller square has a side length of 4 in. what is the ratio of the areas of the larger square to the smallest square?

Answer 1

If the bigger square has a perimeter of 36 in, then the side length is:

`(36)/(4)=\text{ 9}`

thus, the area of the bigger square is:

`A_1\text{ = 9x9 = 81}`

on the other hand, the area of the smallest square would be:

`A_2\text{ = 4 x 4 = 16}`

so that, the ratio of the areas of the larger square to the smallest square is:

`(A_1)/(A_2)\text{ = }(81)/(16)\text{= 5.06}`

then, the correct answer is:

`\text{ }(81)/(16)\text{= 5.06}`