Question

VFind the area of the figure. (Sides meet at right angles.)11 yd3 yd9 yd9 yd5 yd5 yd4 yd4 yd

Answer 1

Given the figure shown in the exercise, you can edit it as follows (See the picture attached):

Notice that you have now a large rectangle and a small rectangle inside the square. Therefore, you can find the area of the original figure by subtracting the area of the small rectangle from the area of the larger one:

`A_f=A_1-A_2`

The area of a rectangle can be found with this formula:

`A=lw`

Where "l" is the length and "w" is the width.

In this case, you can identify that the dimensions of the large rectangle are:

`\begin{gathered} l_1=11yd \\ w_1=9yd \end{gathered}`

And the dimensions of the small rectangle are:

`\begin{gathered} l_2=5yd \\ w_2=3yd \end{gathered}`

Then, you can set up that:

`A_f=(11yd)(9yd)-(5yd)(3yd)`

Finally, evaluating, you get:

`\begin{gathered} A_f=99yd^2-15yd^2 \\ A_f=84yd^2 \end{gathered}`

Hence, the answer is:

`A_f=84\text{ }yd^2`