Question

If angle ABC = 67, angle TBC = x+48 and angle ABT = x+31 what is x?

Answer 1

`m\angle ABT\text{ + m}\angle TBC\text{ = m}\angle ABC`

x + 31 + x + 48 = 67

x + x +31 + 48 = 67

2x +79 = 67

2x = 67 -79

2x = -12

Divide both sides by 2, we get,

x = -12/2

x = -6

Solution: x = - 6