Question

Given the area of a triangle is 20, base is (x+2) and height is x. Find the valueof x and the dimensions of the triangle.

Answer 1

we have the following:

`\begin{gathered} A=(b\cdot h)/(2) \\ b=x+2 \\ h=x \\ A=20 \end{gathered}`

replacing:

`\begin{gathered} 20=((x+2)\cdot x)/(2) \\ 20\cdot2=x^2+2x \\ x^2+2x-40=0 \\ x=5.4;x=-7.4 \end{gathered}`

therefore, the answer is:

x = 5.4

base (x+2) = 7.4

height = 5.4

`\begin{gathered} A=(7.4\cdot5.4)/(2) \\ A=20 \end{gathered}`