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Jason and Melvin are swimming across a lake that is 4 miles long Jason swam 2.5 miles in two hours and Melvin swam 4 miles in 2.5 hours what is the average rate in them miles per hour that Jason swam

Jason and Melvin are swimming across a lake that is 4 miles long Jason swam 2.5 miles-example-1
User Dbaston
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1 Answer

6 votes

1.25

Step-by-step explanation

The velocity of an object is the rate of change of its position with respect to a frame of reference, to find the average rate use the expression:


rate=\frac{total\text{ distance}}{total\text{ }time}

Step 1

For jason

a)Let


\begin{gathered} total\text{ distace=2.5 miles} \\ time\text{ = 2 hours} \end{gathered}

now, replace in the expression:


\begin{gathered} rate=\frac{total\text{ distance}}{total\text{ }time} \\ rate=\frac{2.5\text{ miles}}{2\text{ hours}} \\ rate=1.25\text{ }(m)/(h) \end{gathered}

therefore, the answer ie 1.25

1 hope this helps you .25

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User Jacob Curtis
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