Question

What is the trigonometric ratio for COS C ?Enter your answer in the boxes. Simplify ifnecessary.

Answer 1

The guy above me is correct the answer is: 15/17

Answer 2

`\begin{gathered} \text{ Given an acute angle }\theta\text{ in a right-angled triangle, then} \\ \end{gathered}`
`\cos \theta=\frac{\text{ length of the side adjacent to angle }\theta}{\text{ length of the hypotenuse}}`

The side adjacent to The length of BC = 45

The length of AC = 51

Therefore,

`\cos C=(45)/(51)=(15)/(17)`