Question

Hello, I need some help with this precalculus question for my homework, please? I just need help with the second portion of this question. HW Q5

Answer 1

Step-by-step explanation

`\begin{gathered} x(x+3)=10 \\ x^2+3x-10=0 \\ (x+5)(x-2)=0 \end{gathered}`

The above equation has two solutions. x = -5 and x = 2.

However, since the original equation is in terms of logarithms we only take the positive solution which would be x = 2.