(m ^(2) - 7m - 11) / (m - 8)how do I solve?

Question

`(m ^(2) - 7m - 11) / (m - 8)`how do I solve?

Answer 1

`m+(m-11)/(m-8)`

Explanation:

We have the following division

`\begin{gathered} (m^2-7m-11)/(m-8) \\ \text{what is equal to:} \\ (m^2-7m-11)/(m-8) \end{gathered}`

Now we carry out the operation and we have:

We divide the quotients of the higher degree terms of the numerator and the divisor

`(m^2)/(m)=m`

Then we multiply this quotient by the denominator

`m\cdot(m-8)=m^2-8m`

Now, we subtract this value from the numerator and we have

`\begin{gathered} m^2-7m-11-(m^2-8m)=m^2-7m-11-m^2+8m=m-11 \\ \end{gathered}`

Therefore the final result would be

`(m^2-7m-11)/(m-8)=m+(m-11)/(m-8)`