Question

Challenge The manager of a restaurant wants to add two new sidedishes to the menu. She asked a sample of customers during one ofher evening shifts which side dish he/she prefers. The table showsthe customers' responses. Find the experimental probability that acustomer prefers either baked potato or asparagus. Find theexperimental probability that a customer prefers either steamedbroccoli or sweet potato. Use pencil and paper. Based on thesefrequencies, which two side dishes do you think the manager shouldRestaurant MenuNumber ofSide Dish CustomersBaked127PotatoSteamed 44BroccoliAsparagus 95The experimental probability that a customer prefers a baked potato or asparagus is(Round to the nearest percent as needed.)%.1

Answer 1

To find all the probabilities we will divide the "favorable cases" by the total (customer). The total of customers is 127 + 44 + 95 +104 = 370.

a)

What's the probability that the customer prefers either backed potato or asparagus? The number of customers that chose baked potato was 127, and aspararagus , therefore we have 127 + 95 = 222 favorable cases. The probability will be

`P=(222)/(370)=0.6=60\%`

The probability is 60%

b)

Here we will follow the same logic, we will sum customers that picked sweet potato and steamed broccoli and divide by the total. The favorable cases are 104 + 44 = 148, therefore

`P=(148)/(370)=0.4=40\%`

The probability is 40%

95