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A bag contains 9 white counters, 8 black counters, and 6 green counters. What is the probability of drawing(a) a white counter or a green counter? (b) a black counter or a green counter? (c) not a green counter?

User Gjunkie
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1 Answer

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In order to determine the probability fr each case, it is necessary to calculate the quotient between the number of desired cases and the total number of options.

a) a white counter or a green counter

Consider that there are 9 white counters and 6 green counters, that is, there are 9 + 6 = 15 counters with some characteristic you want.

The total number of counters are 9 + 8 + 6 = 23 counters. Then, the probability is:

P = 15/23 it is not possible to simplify the fractions

b) a black counter or a green counter

There are 8 black counters and 6 green counters, that is, 8 + 6 = 14 counters.

The probability is:

P = 14/23 it is not possible to simplify the fraction

c) not a green counter

It means only white and black counter. Then, there are 9 + 8 = 17 counters with a desired characteristic. The probability is:

P = 17/23