Question

Given −^2+ 2 − 8 evaluate when, = −4 and = −2.

Answer 1

Given:

`-x^2+2xy-8`

Substitute x=-4 and y=-2, we get

`-(-4)^2+2(-4)(-2)-8`

`=-16+16-8`

`=-8`

Hence the given polynomial is -8 when x=-4 and y=-2.