![y\text{ = }(-1)/(3)x\text{ + 2 (option 3)}](https://img.qammunity.org/2023/formulas/mathematics/college/ce480iftk63zr1b9cyv75otavg9vohckif.png)
Step-by-step explanation:
Equation of line:
y = mx + c
we need to find the slope of the line using any two points:
using points (-3, 3) and (3, 1)
![m\text{ = }(y_2-y_1)/(x_2-x_1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/sukh4lu5s7fgiz5v423o6usjd9gul4kfrj.png)
![\begin{gathered} x_1=-3,y_1=3,x_2=3,y_2\text{ = 1} \\ \text{slope = }(1-3)/(3-(-3))=(-2)/(3+3) \\ \text{slope = }(-2)/(6)=\text{ -1/3} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/o27ucajzqou2rnctjgi3ydvzx4tfl92bcz.png)
c = y -intercept
This is the point the line crosses the y axis. The line cross y axis at y = 2
c = 2
The equation of line becomes:
![y\text{ = }(-1)/(3)x\text{ + 2 (option 3)}](https://img.qammunity.org/2023/formulas/mathematics/college/ce480iftk63zr1b9cyv75otavg9vohckif.png)