Answer:
![y\text{ = -}(5)/(2)x\text{ + 3}](https://img.qammunity.org/2023/formulas/mathematics/college/bodtafgc1iyp1fsl9odkyp2qpdm197k1ip.png)
Step-by-step explanation:
The general equation of a straight line is:
![y\text{ = mx + b}](https://img.qammunity.org/2023/formulas/mathematics/college/yw2q0p6vyzh9spy336dumq3zdpb67k7euq.png)
where m is the slope and b is the y-intercept
For the line given, the slope value is 2/5
When two lines are perpendicular, the product of their slopes is -1
Thus, from the slope of the first line, we can get the slope of the second line
Let us call the slope of the second line m2
![\begin{gathered} m_2*\text{ }(2)/(5)\text{ = -1} \\ \\ m_2\text{ = -}(5)/(2) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/yjnb77kxgq34fcikmhew2mosv074yrb2rj.png)
We have the slope of the second line and a point (2,-2) through which the line passes
We can write the equation of the line using the point-slope form as follows:
![\begin{gathered} y-y_1=m(x-x_1) \\ y+\text{ 2 = -}(5)/(2)(x-2) \\ \\ y\text{ + 2 = -}(5)/(2)x\text{ +5} \\ \\ y\text{ = -}(5)/(2)x\text{ + 5-2} \\ \\ y\text{ = -}(5)/(2)x\text{ + 3} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/s1grre82ra8ctwxvwy4fpofy5x5v2iwil3.png)