Find the moles of CaCO3 in 23.4 g of calcium carbonate

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Tonithy asked Dec 9, 2022

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Find the moles of CaCO3 in 23.4 g of calcium carbonate

Chemistry
high-school

Tonithy asked Dec 9, 2022

by Tonithy

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11 votes

Answer:

0.0326 moles

explanation

Alphy answered Dec 11, 2022

by Alphy

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16 votes

Answer:

0.234 mol

Step-by-step explanation:

m(CaCO3) = 23.4g

n(CaCO3) = ?

M(CaCO3) = 100.09 g/mol

n = m/M

n(CaCO3) = 23.4 / 100.09

= 0.234 mol (3 s.f.)

Looney answered Dec 13, 2022

by Looney

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