Question

2.Cowboys kicker Brett Maher kicks the ball off at 25 m/s at an angle of 60° determine the time of flight

Answer 1

Given data:

* The initial velocity of the ball is 25 m/s.

* The angle of the initial velocity with the horizontal is 60 degree.

* The final vertical velocity of the ball at the maximum height is 0 m/s.

Solution:

By the kinematics equation, the time taken by the projectile to reach the maximum height is,

`v^{}-u=-gt`

where v is the final vertical velocity at the maximum, u is the initial vertical velocity, g is the acceleration due to gravity, and t is the time taken to reach the maximum height,

`\begin{gathered} 0-25\sin (60^(\circ))=-9.8* t \\ -21.65=-9.8t \\ t=(-21.65)/(-9.8) \\ t=2.21\text{ s} \end{gathered}`

Thus, the time of flight of the ball is,