Question

The flux through the coils of asolenoid changes from6.78*10^-4 Wb to 1.33*10^-4 Wbin 0.0333 s. If the solenoid has605 loops, how much EMF isgenerated?(Unit = Volts)

Answer 1

We can use the next formula in order to calculate the EMF

`\text{EMF}=-N(\Delta\Phi)/(\Delta t)`

where N is the number of loops, Φ is the magnetic flux and t is the time.

when t=0 the flux is 6.78*10^-4 Wb

when t=0.0333 the flux is 1.33*10^-4 Wb

N=605 loops

we substitute the values

`\text{EMF}=-605*(1.33*10^(-4)-6.78*10^(-4))/(0.0333)=9.90165V`

The EMF is 9.9 V