a.
The intensity of a wave (I) at a surface is equal to :
I = P / A
Where:
P = power output of the speaker = 1 w
A= surface area of the speaker = 0.05 m2
I = 1 w / 0.05m^2 = 20 w/m^2
b.
The intensity at a distance r from the speaker is found by:
I = P / (4πr^2)
Solve for r:
![r=\sqrt[]{(P)/(4\pi I)}](https://img.qammunity.org/2023/formulas/physics/college/ffc5ppt5zq94a1wnnu8pskgbd0hhvfhvbz.png)
![r=\sqrt[]{\frac{1W}{4\pi(0.1w/m^2)^{}}}](https://img.qammunity.org/2023/formulas/physics/college/ohlie668gg0fey7spwlk2srr0srmm7p3c0.png)
r=0.892 m