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write the equation of the line that is perpendicular to the graph of 3x - y = 5, and whose y-intercept is (0,-7)

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\begin{gathered} \text{Isolate y} \\ -y=-3x+5 \\ y=3x-5 \\ \\ Slope\text{ for perpendicular line} \\ (-1)/(3) \\ \\ \text{Use values} \\ y=mx+b \\ -7=-(1)/(3)(0)+b \\ -7=b \\ \\ \text{Equation of the perpendicular line} \\ y=-(1)/(3)x-7 \end{gathered}

User Nick Rolando
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