In the table, we are given the probability of each outcome, that is, selecting no people that have received a ticket, one, two, ...
Item a:
We look at the table, find the value of P when x = 1.
P(x = 1) = 0.2241
Item b:
We look at the table, find the value of P when x = 5. So
P(x = 5) = 0.0261
Item c:
All options greater than 1. So
P(x > 1) = P(x = 2) + P(x = 3) + P(x = 4) + P(x = 5) + P(x = 6+) = 0.2233 + 0.1567 + 0.0285 + 0.0261 + 0.0000 = 0.4346
P(x > 1) = 0.4346
Item d:
The only value that is in this interval is x = 0, since in this exercise we do not have negative values of x. So
P(x <= 0) = P(x = 0) = 0.3413