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What us the 20th term of the arithmetic sequence?2, -5, -12, -19,...

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Answer:

The 20th term is;


a_(20)=-131

Step-by-step explanation:

Given the arithemetic sequence;


2,-5,-12,-19,\ldots

The first term is 2;


a=2

The common difference d is;


\begin{gathered} d=-5-2 \\ d=-7 \end{gathered}

The nth term of an arithemetic sequence can be calculated using the formula;


a_n=a+(n-1)d

substituting for the 20th term, n=20;


\begin{gathered} a_(20)=2+(20-1)(-7) \\ a_(20)=2+(19)(-7) \\ a_(20)=2-133 \\ a_(20)=-131 \end{gathered}

Therefore, the 20th term is;


a_(20)=-131

User Ricardo Anjos
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