We can find the area of a sector of a circle using the following equation:
![A=(N)/(360)(\pi\cdot r^2)](https://img.qammunity.org/2023/formulas/mathematics/college/j8x5gq99f7nqdbwn5s41m7drzg9youj75n.png)
where N is the angle in degrees and r is the radius. In this case, we have the following:
![\begin{gathered} N=70 \\ r=10 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/mm3ograv2pyxb0hiqclcpqcxpwpo550alx.png)
using the formula, we get:
![\begin{gathered} A=(70)/(360)(3.14\cdot(10)^2)=(70)/(360)(314)=61.1 \\ \Rightarrow A=61.1m^2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/k7y1j1hzubia5igpliqvcw7tfoum9sub0g.png)
therefore, the area of the sector formed by angle NMP is 61.1m^2