Question

The sides 67 d triangle measure 5,9, and 10. Find the perimeter of a similar triangle whose longest side measures 15.

Answer 1

the sides of a triangle are: 5,9,10, and we know that a similar trianlge has his longest side equal to 15 so we can find the other sides of the triangle with the ratio between the similar triangles so the ratio is:

`\begin{gathered} r=(15)/(10) \\ r=1.5 \end{gathered}`

now we know that the other sides will be:

`\begin{gathered} x=5\cdot1.5=7.5 \\ y=9\cdot1.5=13.5 \end{gathered}`

So the perimeter will be:

`\begin{gathered} P=15+13.5+7.5 \\ P=36 \end{gathered}`