The given information is:
- Bob places $7500 in the account
- It pays 4% interest compounded each year
- No withdrawals are made from the account
Part A. Find the amount in the account at the end of 1 year:
So, at the end of the first year, Bob will have in the account the money he placed there plus the money he earned from the 4% interest.
The money from interest is given by:
![\begin{gathered} I=P*r \\ \text{ Where I is the money he earned, P is the principal and r the interest rate} \\ I=7500*0.04=300 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/wws6owfrohgtnrtjwkszdquxqr2husf2h7.png)
Therefore, the amount in the account at the end of 1 year is:
![\begin{gathered} A=P+I \\ A=7500+300 \\ A=7800 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/9b100mtg6m39azoqx40khaii7n0xe598yg.png)
Answer: $7800
Part B. Find the amount in the account at the end of 2 years.
So, at the beginning of year 2 Bob has $7800, let's find the interest at the end of year 2:
![I=7800*0.04=312](https://img.qammunity.org/2023/formulas/mathematics/college/5i5epku5ukzluxyiewi947afcwhprou33o.png)
At the end of year 2, he will have in the account the following amount:
![\begin{gathered} A=7800+312 \\ A=8112 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/pgkvyemuig5uq7u5fwoig3itrdir31i2t8.png)
Answer: $8112