Question

If log2(7x+4) =2 you may enter value or round to 4 decimal place

Answer 1

Okay, here we have this:

Considering the provided equation, we are going to solve it, so we obtain the following:

`\begin{gathered} log_2(7x+4)=2 \\ 7x+4=2^2 \\ 7x+4=4 \\ 7x=4-4 \\ 7x=0 \\ x=(0)/(7) \\ x=0 \end{gathered}`

Finally we obtain that x is equal to 0.