Question

We need detailed step by step directions on how to figure out the answer

Answer 1

Given:

`x=22\text{ ft ; }y=20\text{ ft ; z=}18\text{ ft}`
`x^2=y^2+z^2-2yz\cos X`
`\begin{gathered} 22^2=20^2+18^2-2(20)(18)\cos X \\ 484=400+324-720\cos X \\ 484=724-720\cos X \\ 720\cos X=724-484 \\ 720\cos X=240 \\ \cos X=(240)/(720) \\ \cos X=(1)/(3) \\ X=\cos ^(-1)((1)/(3)) \\ X=70.53\degree \end{gathered}`