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User Ashford
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Using the tangent relation,


\begin{gathered} m\angle APB\text{ =}\frac{\text{ major arc - minor arc}}{2} \\ \text{Let the minor arc = x}^0 \\ \text{ Then, the major arc = 3x}^0 \end{gathered}

The angles subtended by the major and minor arc sums up to 360 degrees.


\begin{gathered} \text{ Therefore,} \\ 3x^{}+x^{}=4x \\ 4x\text{ = 360} \\ x=90^0 \end{gathered}

That means, the angle subtended by the major arc


=3\text{ }*90^0=270^0

While the angle subtended by the minor arc is


90^0

Applying the tangent relation above


m\angle APB\text{ = }(270-90)/(2)=(180)/(2)=90^0

Therefore, t

User Neil Knight
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