A 5kg block slides across a horizontal table surface with a coefficient of friction of 0.21. What is the friction force the block experiences?

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asked Sep 15, 2023 224k views

2 votes

A 5kg block slides across a horizontal table surface with a coefficient of friction of 0.21. What is the friction force the block experiences?

Physics
college

Vikram Pathania asked

by Vikram Pathania

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1 Answer

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$\begin{gathered} m=5\operatorname{kg},g=9.81m/s^2 \\ \mu_k=0.21 \\ Ff=\text{?} \\ Ff=\text{ N}\cdot\mu_k \\ \text{From the fr}ee\text{ body diagram} \\ \uparrow+\Sigma Fy=0 \\ N-mg=0 \\ N=mg \\ \text{Hence} \\ Ff=\text{ N}\cdot\mu_k \\ Ff=\text{ }mg\cdot\mu_k \\ Ff=(5\operatorname{kg})(9.81m/s^2)(0.21) \\ Ff=10.3N \\ \text{The friction force is 10.3N} \end{gathered}$