Given data:
The current is I=14.72 A.
The time taken is t=22.94 s.
The charge pass through the wire can be calculated as,
![\begin{gathered} Q=It \\ Q=(14.72)(22.94) \\ Q=337.6\text{ C} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/rqp2e5mtsegu1kc8oebbxddw3n4igt1ssa.png)
If the charge on an electron is e=1.6x10⁻¹⁹ C, the the number of electrons pass through the wire will be,
![\begin{gathered} n=(Q)/(e) \\ n=(337.6)/(1.6*10^(-19)) \\ n=211*10^(19) \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/i55nrjn5fke8q1ww5bga76bbmmsv9zpy2n.png)
Thus, the number of electrons pass through the wire in 22.94 s is 211x10¹⁹.
Final Answer: 211x10¹⁹