38.3k views
5 votes
Hi, can you help me to solve this exercise, please!

Hi, can you help me to solve this exercise, please!-example-1
User Publicgk
by
9.4k points

1 Answer

2 votes

Use the next trigonometric ratio for angle 60º in a right triangle:


\cos 60º=\frac{\text{adjacent leg}}{hypotenuse}=(WX)/(YX)

Use the given data to solve WX:


\begin{gathered} \cos 60º=\frac{WX}{6\sqrt[]{3}} \\ \\ WX=6\sqrt[]{3}*\cos 60 \\ \\ WX=6\sqrt[]{3}*(1)/(2) \\ \\ WX=\frac{6\sqrt[]{3}}{2} \\ \\ WX=3\sqrt[]{3} \end{gathered}Then, WX is:
WX=3\sqrt[]{3}

User Waqar UlHaq
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories