From the conclusion of the hypothesis:

The null hypothesis is that mean number is equal to 48
The alternate hypothesis is that mean number is greater than 48
Option A is the correct answer
Hence the test statistics will be given as
![\begin{gathered} t_{\text{test}}=\frac{\bar{x}-\mu}{\frac{s}{\sqrt[]{n}}} \\ t_{\text{test}}=\frac{57.7-48}{\frac{16.1}{\sqrt[]{10}}} \\ t_{\text{test}}=1.91 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/pq4dx3itwcu0qr1mx19w2lqgq5x2uuvvfk.png)
The p - value of the t - test above at degree of freedom of 9 is

Since the p- value is greater than the significance level, do not reject the null hypothesis
So the conclusion is that
Failed to reject H₀, there is not sufficient evidence to support the claim.