Question

I need help solving this problem.I have to find the missing sides of the special right triangle

Answer 1

As given by the question

There are given that the right angle triangle

Now,

From the triangle, first, find the value of ST

So,

To find the value of ST, use the sine function

Then,

`\sin 30^(\circ)=(ST)/(RT)`

Then,

`\begin{gathered} \sin 30^(\circ)=(ST)/(RT) \\ (1)/(2)^{}=(ST)/(12) \\ 2* ST=12 \\ ST=(12)/(2) \\ ST=6 \end{gathered}`

Now,

To find the value of RS, use sine function also

So,

`\begin{gathered} \sin 60=(RS)/(RT) \\ \frac{\sqrt[]{3}}{2}=(RS)/(12) \\ 2* RS=12*\sqrt[]{3} \\ RS=\frac{12*\sqrt[]{3}}{2} \\ RS=6\sqrt[]{3} \end{gathered}`

Hence, the value of ST and RS is shown below: