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How much heat transfer (in kilocalories) is required to thaw a 0.450-kg package of frozen vegetables originally at 0ºC if their heat of fusion is the same as that of water?q= 1.5 x 10^5 J (answer from book)

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We are asked to determine the amount of heat requiered to thaw a pacakge of vegetables. To do that we will use the following formula:


Q=mL_f

This is the formula of latent heat of fusion, where "Q" is the amount of heat, "m" is the mass, and Lf the heat of fusion. The heat of fusion is:


L_f=0.334\frac{J}{\operatorname{kg}}

Which is the heat of fusion of water. Replacing the values:


Q=(0.450\operatorname{kg})(0.334\frac{J}{\operatorname{kg}})

Solving the operations:


Q=0.1503J

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