Given:
My speed = 20 m/s
Speed of car 2 = 30 m/s
Frequency of police car = 600 Hz.
Let's find the frequency I hear.
Apply Doppler equation since the source and observer are towrads each other
![Fa=((V+V_o)/(V-V_s))F_o](https://img.qammunity.org/2023/formulas/physics/college/ypva3v6qbby1lg3qibayu4jalzgk4f563c.png)
Where:
V is the speed of sound = 340 m/s.
Vo is the speed of the observer(my speed) = 20 m/s
Vs is the speed of source(speed of police car) = 30 m/s
Fo = 600 Hz.
Thus, we have:
![\begin{gathered} Fa=((340+20)/(340-30))600 \\ \\ Fa=((360)/(310))600 \\ \\ Fa=696.8\text{ Hz} \end{gathered}](https://img.qammunity.org/2023/formulas/physics/college/rgs3xqb3vzubwodeambd5sw8qpa4owoz02.png)
Therefore, the frequency you will hear is 696.8 Hz.
ANSWER:
696.8 Hz.