Question

Y=2x2 + 2x + 1y= 2x +3What is the solution to this system of equations?

Answer 1

`\begin{gathered} y=2x^2+2x+1 \\ y=2x+3 \end{gathered}`

Therefore,

`\begin{gathered} 2x+3=2x^2+2x+1 \\ 2x^2+2x-2x+1-3=0 \\ 2x^2-2=0 \\ 2(x^2-1)=0 \\ (x-1)(x+1)=0 \\ x=1 \\ or \\ x=-1 \end{gathered}`

substitute the values of x in the equations

`\begin{gathered} y=2(1)+3 \\ y=6 \\ \\ y=2(-1)+3 \\ y=1 \end{gathered}`

Therefore,

(1, 6) (-1, 1)