A) We calculate the scale point multypling the coordinates of the original point by the scale factor:
![\begin{gathered} P=(6,-12) \\ k=(1)/(2) \\ P\text{'}=((1)/(2)\cdot6,(1)/(2)\cdot(-12))=(3,-6) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/lqyhn8tnypuvy6oe0v5yr7v8q3r85cd68b.png)
The transformed point is P'=(3,-6)
B) We have one point A=(-8,-5) that is reflected over a point C=(0,-3). The image is point B.
As it is reflected, the B point is at the same distance from C=(0,-3) than A.
We can see this in a graph:
A is at a distance of 8 units in the x-axis and 2 units in the y-axis.
Then, we add this distance to C (in the opposite direction from A) in order to get B.
B=(0,-3)+(8,2)=(8,-1).
The point B is (8,-1).