Answer:
a. 0.964 moles of N₂O will be produced
b. mass of N₂ required = 7.31 g of N₂
c. Number of particles of N₂= 5.87 * 10²² molecules of N₂
Step-by-step explanation:
a. Balanced equation of the reaction is given below: 2N₂ + O₂ ---> 2N₂O
Molar mass of N₂ = 28 g/mol
molar mass of O₂ = 32 g/mol
molar mas of N₂O = 44g/mol
From the equation of reaction, 2 moles of nitrogen gas reacts with 1 mole of oxygen gas to produce 2 moles of N₂O
number of moles of N₂ present in 26.5 g = 26.5 g/28 g/mol = 0.946 moles
Since oxygen gas is in excess in the reaction, the limiting reactant is N₂
Mole ratio of N₂ to N₂O is 1 : 1
Therefore, 0.964 moles of N₂ will react with excess oxygen gas to produce 0.964 moles of N₂O
b. number of moles of N₂O in 11.5 g of N₂O = 11.5/44 = 0.261 moles
0.261 moles of N₂O will be produced by 0.261 moles of N₂
mass of N₂ present in 0.261 moles = 0.261 * 28
mass of N₂ required = 7.31 g of N₂
c. number of moles of O₂ present in 1.56 g of O₂ = 1.56/32 = 0.04875moles
Moles of N₂ required to react with 0.4875 moles of O₂ = 2 * 0.04875 = 0.0975 moles
Number of particles of N₂ present in 0.0975 moles = 6.02 * 10²³ * 0.0975
Number of particles = 5.87 * 10²² molecules of N₂