Question

How deep under water must we dive for the pressure to become 6.41 times the pressure at the surface? Include units in your answer. Answer must be in 3 significant digits.

Answer 1

`\begin{gathered} \rho=1000\text{ kg/m}^3 \\ g=9.81\text{ m/s}^2 \\ h=? \\ P1=P_(atm)=101293Pa \\ P2=P_(atm)+\rho gh \\ P2=6.41P_(atm) \\ P_(atm)+\rho gh=6.41P_(atm) \\ \rho gh=6.41P_(atm)-P_(atm) \\ \rho gh=5.41P_(atm) \\ h=(5.41P_(atm))/(\rho g) \\ h=\frac{5.41(101293Pa)}{(1000\text{ kg/m}^3)(9.81\text{ m/s}^2)} \\ h=55.861m \\ At\text{ 55.861m deep the pressure will be 6.41 times the pressure } \\ \text{at the surface} \end{gathered}`