Question

10y-20x+50=0 this is a linear equation needed to be put in slope intercept form

Answer 1

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Write the given linear equation

`10y-20x+50`

STEP 2: Subtract 50 from both sides

`\begin{gathered} 10y-20x+50-50=0-50 \\ 10y-20x=-50 \end{gathered}`

STEP 3: Add 20x to both sides

`\begin{gathered} 10y-20x+20x=-50+20x \\ 10y=-50+20x \end{gathered}`

STEP 4: Divide both sides by 10

`\begin{gathered} (10y)/(10)=(-50+20x)/(10) \\ \\ y=(-50)/(10)+(20x)/(10) \\ y=-5+2x \\ y=2x-5 \end{gathered}`

Since the slope intercept form of a line is given as:

`\begin{gathered} y=mx+c \\ where\text{ m is the slope} \\ c\text{ is the y-intercept} \end{gathered}`

Hence, the slope intercept form is given as:

`y=2x-5`