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If f(x) = 57, what is the value of f(-8), to the nearest tenth (ifnecessary)?

1 Answer

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You have the following function f(x):

f(x) = -2/(5x³)

In order to calculate the previous function for x=-8, that is, in order to calculate f(-8) you simply substitute x by -8 into f(x) and do the calculations, just as follow:

f(-8) = -2/(5(-8)³)

First, you solve the exponentiation of (-8)³, the result of this is a negative number, because a negative number exponentiated to a even integer result in another negative number. Then you have (-8)³ = -512

f(-8) = -2/(5(-8)³) = -2 / (5(-512))

next, you multiply 5 by -512:

-2 / (5(-512)) = -2 / (-2560)

next, you can eliminate the minus sign beacuse it is both numerator and denominator, remember that - / - = +

-2 / (-2560) = 2 / 2560

finally, you use a calculator to do the previous operation

2 / 2560 = 0.00078

In order to approximate the result to its nearest tenth you have

0.00078 ≈ 0.0

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