The Solution:'
The given data is:
![0,0,0,0,0,0,0,1,1,1,1,2,2,2,2,2,2,2,3,3,3,3,4,5,9](https://img.qammunity.org/2023/formulas/mathematics/college/ixagvfodon9cy69x1mlwkr3m77iikj9kd5.png)
We are required to find the minimum, maximum, first quartile, third quartile, and median.
Step 1:
The total number of data is 25.
![N=25](https://img.qammunity.org/2023/formulas/mathematics/college/4gz99veox1utaf2t7j9ovmanm8g5btqgrs.png)
The minimum = 0
The maximum = 9
The first Quartile is
![Q_1=((N+1)/(4))\text{th}=((25+1)/(4))th=(26)/(4)th=6.5th\Rightarrow0](https://img.qammunity.org/2023/formulas/mathematics/college/14bl1rrw48mxcuwek9xzzlogkudxxh8aog.png)
6.5th means the number in the 6.5th position when the data is arranged in ascending order.
The third Quartile is
![Q_1=(3)/(4)(N+1)\text{th}=(3)/(4)(25+1)th=(3*26)/(4)th=19.5th\Rightarrow3](https://img.qammunity.org/2023/formulas/mathematics/college/oim8k3lqwam9a9j8htgysxu69rk253pwlh.png)
The median is
![Q_1=((N+1)/(2))\text{th}=((25+1)/(2))th=(26)/(2)th=13th\Rightarrow2](https://img.qammunity.org/2023/formulas/mathematics/college/14ddthktuoky5g7brjb3q5klhbrev3lewf.png)
Therefore, the correct answers:
min=0,max=9, first Quartile=0, third Quartile=3, median=2.