SOLUTION:
Step 1:
In this question, we are given the following:
Step 2:
We need to get the values of B, b, and c.
Part A:
To get the value of b, we have to do the following:
![\begin{gathered} \tan 29.8^0=(7.8)/(b) \\ b\text{ =}(7.8)/(\tan 29.8^0) \\ b\text{ = }(7.8)/(0.5727) \\ b\text{ = 13.619} \\ \text{b }\approx\text{ 13. 6 ( 3 significant figures)} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/uk0uo6mup8l1jzkqvo105ti4p28ut0p7hz.png)
Part B:
To get the value of c, we need to do the following:
Using Pythagoras' theorem, we have that:
![\begin{gathered} c^2=(7.8)^2+(13.6)^2 \\ c^2=\text{ 60.84 + 184.96} \\ c^2=245.8 \\ \text{square}-\text{root both sides, we have that:} \\ \text{c = 15.678} \\ \text{c }\approx\text{ 15. 7 ( 3 significant figures)} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ickvd9i2yngy4dudak8256p06fu2wxeqec.png)
Part C:
To get the value of B, we need to do the following:
![\begin{gathered} ^{\angle\text{ A+ }\angle B\text{ +}\angle C=180^0(\text{ Sum of angles in a triangle)}} \\ 29.8^0+\angle B+90^0=180^0 \\ 119.8^{\text{ 0}}+\text{ }\angle B=180^0 \\ \angle B=180^0-119.8^0^{}^{}^{}^{} \\ \angle B=60.2^0(\text{ 3 significant figures)} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/7hf0lo7hxczri1htxtk7eid6ntquqhmeke.png)