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If two terms of an arithmetic sequence are a11 = 26 and a15 = −10, what is a28? −226 −217 −127 −20

If two terms of an arithmetic sequence are a11 = 26 and a15 = −10, what is a28? −226 −217 −127 −20-example-1

1 Answer

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An arithmetic sequence is given by the following formula:

an = a1 + d(n - 1)

Where a1 is the first term and d is the common difference. In this case, we are given the values of a11 and a15, then we can formulate the following expressions:

a11 = a1 + d(11 - 1)

a11 = a1 + d(10)

a11 = a1 + 10d

26 = a1 + 10d

Similarly for a15:

a15 = a1 + d(15 - 1)

a15 = a1 + 14d

-10 = a1 + 14d

Then, we got two equations:

26 = a1 + 10d

-10 = a1 + 14d

By subtracting the first from the second one, we get:

-10 - 26 = a1 - a1 + 14d - 10d

-36 = 4d

From this equation, we can solve for d by dividing both sides by 4, like this:

-36/4 = 4d/4

-9 = d

d = -9

Now that we know the value of d, we can replace it into 26 = a1 + 10d to find a1, like this:

26 = a1 + 10(-9)

26 = a1 - 90

26 + 90 = a1 - 90 + 90

116 = a1 + 0

a1 = 116

Then, a1 = 116 and we can rewrite the model like this:

an = 116 - 9(n-1)

By replacing 28 for n we get the value of a28:

a28 = 116 - 9(28 - 1)

a28 = 116 - 9(27)

a28 = 116 - 243

a28 = -127

Then, a28 = -127, the third option is the correct answer

User Glade Mellor
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