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the parent quadratic function g(x) = x^2 is translated 3 units up and 4 units left, and stretched by a factor of 2. write the resultant function f(x) in vertex form.

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Answer

The resultant function is

f(x) = 2x² + 6x + 13

Step-by-step explanation

When a function g(x) is translated horizontally along the x-axis by a units, the new function is represented as

g(x + a) when the translation is by a units to the left.

g(x - a) when the translation is by a units to the right.

When a function g(x) is translated vertically along the y-axis by b units, the new function is represented as

g(x) + b when the translation is by b units upwards.

g(x) - b when the translation is by b units downwards.

So, for this question, where the function g(x) = x² is translated 3 units up and 4 units left. The new function is

g(x)' = g(x + 3) + 4 = (x + 3)² + 4

The function is now stretched by a factor of 2.

Stretching a function by a factor simply multiplies that function by the factor. So, our function becomes

f(x) = g(x)' = 2 [(x + 3)² + 4]

=

Hope this Helps!!!

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