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Our subjects are 35-44-year-old males whose blood pressures are normally distributed with mean 80 and standard deviation 12;which we can denote by N(80, 12). A borderline hypertensive is defined as a person whose diastolic blood pressure is between 90 and 95 mm Hg inclusive; what proportion of subjects are borderline hypertensive? A hypertensive is a person whose diastolic blood pressure is above 95 mm Hg; what proportion of subjects are hypertensive?

User Pedrodbsa
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1 Answer

7 votes

Given:

mean


\mu=80

standard deviation


\sigma=12

Required:

To defined as a person whose diastolic blood pressure is between 90 and 95 mm Hg inclusive; what proportion of subjects are borderline hypertensive.

For a person whose diastolic blood pressure is above 95 mm Hg; what proportion of subjects are hypertensive.

Step-by-step explanation:


\begin{gathered} P(9095)=1-P(X\leq95) \\ =1-P((X-\mu)/(\sigma)\leq(95-80)/(12)) \\ =1-P(Z\leq1.25) \\ =1-0.8944 \\ =0.1056 \end{gathered}

Final Answer:


\begin{gathered} P(9095)=0.1056 \end{gathered}

User Mr Bhati
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