1. Given the reaction :
• C + 2H2 → CH4
• Mass of CH4 = 104.1g
,
• Molar mass methane(CH4) = 12 + (1*4)= 16g/mol
2. Calculate moles of methane
n = Mass/Mol Mass
= 104.2g/ 16g/mol
=6.5125moles of methane .
3. Determine moles of hydrogen based on molar proportion:
2 moles of hydrogen : 1 mole Methane
so, x moles of hydrogen : 6.5125moles
therefore , molesof hydrogen = 6.5125* 2 /1
=13.025 moles of hydrogen .
= 13.0 moles
This means that 13.0 moles of hydrogen is needed to produce 104.2g CH4