Given:
AB=40 mm
BC=20 mm
AC=27 mm
The objective is to dilate triangle ABD with a scale factor of 2, using A as the centre.
Since, if A is used as center, then the remaining sides will get reduced by a factor of 2.
If AB=40mm,

Similarly if BC=20 mm

And if AC=27 mm

If we construct the dilated triangle AB'C',
Hence, the required dilated triangle AB'C' has been obtained.