Question

How do you condense into single logarithm 3 ln (5х-1) +8 lnx?

Answer 1

We have the expression:

`3\ln (5x-1)+8\ln (x)`

In order to solve to get only one logarithm, we proceed as follows:

`\ln ((5x-1)^3(x)^8)`

That, since:

`\ln (ab)=\ln (a)+\ln (b)`

and:

`\ln (a^n)=n\ln (a)`