Question

11. MZABC = 4x + 16 and mecBX = 3x + 6 if BX bisects ZABC

Answer 1

Given:

`m\angle ABC=4x+16\text{ ; m}\angle\text{CBX}=3x+6`
`m\angle ABC=m\angle CBX+m\angle XBA`
`\vec{BX}\text{ bisects }\angle ABC`
`m\angle CBX=m\angle XBA`
`4x+16=3x+6+3x+6`
`16-6-6=6x-4x`
`2x=4`
`x=2`
`m\angle ABC=24\text{ ; }m\angle CBX=m\angle XBA=12`