Find the combined capacitance of the circuit shown.Group of answer choices7.88 μF6.53 μF4.27 μF5.60 μF

Question

asked Jan 17, 2023 199k views

1 Answer

Max Zolotenko · Answer 1 · 2023-01-21T12:02:58+0000

From the figure,

The 3 capacitors are in paralle.

The equivqlent capacitance of those are:

$C^(\prime)=7+9+2=18\mu F$

This is in series with the fourth capacior.

Thus the equivalent capacitance is:

$\begin{gathered} (1)/(c)=(1)/(18)+(1)/(14)=0.126 \\ \Rightarrow C=7.93\text{ }\mu F \end{gathered}$

Approximating,

The answer is

$7.88\mu F$