Question

Find the combined capacitance of the circuit shown.Group of answer choices7.88 μF6.53 μF4.27 μF5.60 μF

Answer 1

From the figure,

The 3 capacitors are in paralle.

The equivqlent capacitance of those are:

`C^(\prime)=7+9+2=18\mu F`

This is in series with the fourth capacior.

Thus the equivalent capacitance is:

`\begin{gathered} (1)/(c)=(1)/(18)+(1)/(14)=0.126 \\ \Rightarrow C=7.93\text{ }\mu F \end{gathered}`

Approximating,

The answer is

`7.88\mu F`