The cost of each gift wraps g = $3
Let us make the price of one card = c.
Let us make the price of one gift wrap = g.
Now we can create equations from the statements made in the question:
20 cards and 40 gift wraps sell for $160
Meaning:

Let this equation be called equation 1.
Next, we analyze the next part of the question which says:
10 cards and 30 gift wraps sell for $110
Meaning:

Let this be called equation 2.
Let us multiply the second equation by 2

Let this new equation be called equation 3.
We multiplied out equation 2 by 2 because we wanted at least one of the equation coefficients to be the same.
Now we can subtract equation 3 and equation 1.

The cost of each gift wraps g = $3